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from the publisher of The Columbus Book of Euchre |
![]() ![]() ![]() ![]() ![]() ![]() ![]() ![]() ![]() How would you play this hand? |
Presented here are archives of euchre columns by Natty Bumppo, author of The
Columbus Book of Euchre, published on line. |
Assume further that the dealer had no good reason to turn down the club.
To me thats axiomatic: Even if he holds the
jack of hearts and the A-K of clubs with the K-9 of diamonds, I think he must discard the
jack of hearts and pick up the 10 of clubs in most scenarios.
He has no defense to spades, and the discard and pickup make him two-suited with three trump.
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I would (by instinct) lead the 9 of diamonds.
I also believe that it is the correct call mathematically because there seem to be more
possibilities to succeed by getting the off suit out there.
The perfect scenario would be your partners having an ace of diamonds that walks
and a suit lead back that you can ruff.
Making the defenders spend a bower stopping the 9 of diamonds would be probably second
best. The king of diamonds is a nice card
for an end play.
My friend Henry and I tried a few duplicate style samples of the hand. |
Our mathematician my little brother the Ph.D. at Motorola, who tells
engineers where and when (and how high) to jump (we call him Dr. Math)
mused as follows before digging in: |
This is reminiscent of what happens to me when I contract to model some
gizmo at work. I always think the model
will be relatively simple. Then, as the
people I contract with start filling me in on gizmo details, I realize how complicated
the model must be. The result for me is always
overly optimistic deadlines that I cant meet.
I can see the potential for this problem to grow in complexity very rapidly. |
The opponents holding that would most favor leading trump would be an unguarded bower
in each opponents hand. And the holding
I most easily envision as almost requiring a trump lead is an unguarded bower in each
opponents hand and the ace of diamonds also in one of the two opponents hands.
But a 9 of diamonds lead will work even against that if the dealers partner can
trump the diamond and neither of the opponents can or does, or if it is the right hand opponent
who has a lone ace of diamonds and the left hand opponent lays down a bower.
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| The probability that neither opponent has a guarded bower is 57 per cent
which means that 57 per cent of the time, a trump lead will leave the dealer with the
highest trump.
With that exercise complete, the probability that both opponents hold unguarded bowers
(simultaneous unguarded bowers) is fairly easy: Or one-fourth of 1 per cent. |
Yeah, thats infinitesimal. And now it was
all making sense.
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I have found that there are few mathematical solutions, but often mathematical
guidelines. We could do better by doing some
behavior modeling, but our answers would be only as good as our assessment of the behavior.
In the engineering world, where I have served for almost 30 years, I have found that the best
I can do is put the engineers in the ball park.
They do the rest by trial and error. More than
two decimal points of accuracy is wasted compute time. |
OK. We were in the ball park.
Time to play.
Natty Bumppo, author, |
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Double suited, part 1 June 28, 2002
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We know that it means holding a hand containing only two suits, and it can be pretty
valuable. My friend Ron told me that if, as
dealer, he holds the ace, king and 10 of diamonds, the queen of clubs and the 10 of hearts,
and he turns up the 10 of clubs, he will pick up the 10 of clubs and discard the 10 of
hearts.
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On 36 of the 100 hands, Ron made a point picking up the little club; and on
13 of the hands he made two points i.e., he scored on 49 hands, or
almost half of them and he scored big more than an eighth of the time.
It means also, however, that he got euchred 51 per cent of the time.
But also he stopped nine loners held by the opponents, including two hands on which
he scored two points those were 6-point turnarounds! Also he stopped one lone hand his partner would have made: In sum, Ron scored a net of -23 points in the 100 hands (thats minus 23, or an average of nearly a fourth of a point lost every time he picked up that 10 of clubs). |
Being two suited gives you some advantages and a lot of flexibility, but its
not everything (this is not to be taken as an endorsement of John Ellis book!).
Natty Bumppo, author, |
And the webmaster, Gerry Blue, asks
everyone, How would you play this hand?
Natty Bumppo, author, P.S. Black down? |
B held the right, king and nine of hearts and the king and ten of spades.
He took the first trick by ruffing a small diamond with the nine of hearts, and the second by
leading the right bower catching only the queen and ten of trump.
No spades had shown yet.
Natty Bumppo, author, |
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The perfect hand May 24, 2002
[Note: |
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Harvey Lapp, Euchre Central
webmaster and author of the Dear Abbyish euchre advice column Ask Harv, forwarded the
following query to me: |
I'm doing a speech on euchre and I need some statistics. |
Well, I said, shucks, Harv, I think I can do this without Dr. Math (oops!
Thought I could! But I ran it by Dr. Math first,
and he caught a mistake I made. Another mistake
was caught July 21, 2003, by a reader, Eric Reid; and the original of this column
has been revised to take his correction into account.
Here is the corrected poop).
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| Ace of suit, three out of 22; all three, 3/22 of 11.05 per cent
equals 1.5 per cent (thus you have about one chance in sixty-seven of getting the top
three cards of a suit).
King of suit, 2/21; all four, 2/21 of 1.5 per cent equals 0.14 per cent (one chance in 714 of getting the top four). And queen, 1/20; all five, 1/20 of 0.14 per cent equals 0.007 per cent
i.e., less than a hundredth of 1 per cent, or a little less than one
chance out of 14,000 hands of getting a perfect hand (without consideration of
the suit turned or another players making trump. |
But lets back up a little. You dont
need the king or queen for a perfect hand.
Both bowers and ace and any two other trump constitute a perfect hand:
Played correctly (i.e., ruffing with a bower or ace if it is necessary to ruff),
such a hand cannot fail to take all five tricks, from any position.
So: |
Fourth trump, 4, not 2, out of 21:
4/21 of 1.5 per cent equals 0.29 per cent i.e., there is
about one chance in 266 hands of getting the top three cards plus one in a suit.
Fifth trump: |
Now, that does not seem amazingly rare to me, and especially considering this:
A typical game consists of ten hands or more (it would take Dr. Math to
give us a mean of hands per game, but consider:
Three hands is the minimum for a game, and that is quite rare; nineteen is the maximum,
and that is probably even rarer. And it all
depends on the aggressiveness of the players, which is not calculable except statistically:
What does it take to get them to go alone? How
willing are they to risk being euchred?).
Lets take 10 for a conservative average of hands per game.
Natty Bumppo, author, P.S. |
The A-K-10-9 loner revisited April 19, 2002
A critic wrote in response to lastweeks column, The odds that the bowers both are not in your oppo- nents hand are 8/18 times 8/18 = .198 or about 20 per cent. |
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My adviser Dr. Math says that the probability actually is 8/18
times 7/17 = 18.3 per cent (which is the complement of the 81.7 per
cent probability he gave that the opponents have a bower).
In other words, the critic has given my A-K-10-9 loner a slightly better chance of success
than I did.
Natty Bumppo, author, |
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Dwend_98 wrote: |
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Dealers hand
Rons hand |
| Natty Bumppo replies:
Natty Bumppo, author, Dwend: Dwend Natty Bumppo. Natty Bumppo, author, |
Natty Bumppo replies: Natty Bumppo, author, Gerry Blue, EuchreScience webmaster, wrote: Gerry Blue, inventor, the Euchre Laboratory Natty Bumppo: Natty Bumppo, author, [NEXT: |
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Dumb and Dumber March 29, 2002
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Ron, on my right, holds left-queen oftrump (i.e. the jack of hearts and queen of diamonds), the queen of clubs, and the king and ten of hearts.. |
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Rons partner leads the king of spades, Ron sloughs the ten of
hearts, and I take the trick with the nine of diamonds.
Questions: Natty Bumppo, author, Ryan Romanik said: -Ryan! Bumppo: Natty Bumppo The noted euchre webmaster Double says: Double, There is no other card game Bumppo: Natty Bumppo Double: Double, There is no other card game Bumppo: Natty Bumppo Ryan: -Ryan! Bumppo: Natty Bumppo Gerry Blue, EuchreScience webmaster, asks only: Gerry Blue, inventor, the Euchre Laboratory Bumppo: Conclusion: Natty Bumppo, author, |
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